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razvancostin
Pe: 2012-04-09T08:23:11+03:00 In: In:

Algebra clasa a-VIII-a

a=(√3+√2)x(5-√6)+(√2-1).2-3√3
chiar nu stiu sa-l fac
va rog mult sa il faca cineva!!
PLSS

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  1. raluca8

    razvancostin wrote: a=(√3+√2)x(5-√6)+(√2-1)2-3√3

    \rm{(\sqrt3+\sqrt2)\cdot(5-\sqrt6)+(\sqrt2-1)\cdot2-3\sqrt3\bl}

    Te solicit sa confirmi daca enuntul este corect transpus
  2. dan
    expert (VI)

    razvancostin wrote: a=(√3+√2)x(5-√6)+(√2-1)2-3√3
    chiar nu stiu sa-l fac
    va rog mult sa il faca cineva!!
    PLSS


    \rm{ a=(\sqrt3+\sqrt2)\cdot(5-\sqrt6)+(\sqrt2-1)\cdot2-3*\sqrt3=\\ =\underline{5*\sqrt3}+\underline{\underline{5*\sqrt2}}-\underbrace{\sqrt{6*3}}_{\underline{\underline{3*\sqrt2}}}-\underbrace{\sqrt{6*2}}_{\underline{2*\sqrt3}}+\underline{\underline{2*\sqrt2}}-2*1-\underline{3*\sqrt3} = 4*\sqrt2 - 2 \bl

  4. raluca8

    raluca8 wrote: [quote=razvancostin]a=(√3+√2)x(5-√6)+(√2-1)2-3√3

    \rm{(\sqrt3+\sqrt2)\cdot(5-\sqrt6)+(\sqrt2-1)\cdot2-3\sqrt3\bl}

    Te solicit sa confirmi daca enuntul este corect transpus

    \it{(\sqrt3+\sqrt2)\cdot(5-\sqrt6)+(\sqrt2-1)\cdot2-3\sqrt3\bl = 5sqrt3+5\sqrt2-3\sqrt2-2\sqrt3+2\sqrt2-2-3\sqrt3= 4\sqrt2 - 2}

  5. razvancostin

    multumesc

  6. razvancostin

    Va sunt recunascator si daca eram atent il rezolvam si eu,dar dupa ce lati facut mi-am dat seama ce usor era.
    Dar nu inteleg de ce la barem raspunsul este a=3, oricum mi se pare normal cum lati rezolvat.
    Multumesc!

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