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Pe: 2012-09-13T12:30:41+03:00 In: In:

Operatii cu Radical

[(2/√44) – (3/√99) + (10/√1100)] : 5 x (1/√11)
Rezolvarea mea:
( 1/√11 – 1/√11 + 1/√11) x 1/5 x 1/√11 =
1/√11 x 1/√25 x 1/√11 = 1/√3025 = 1/55
M-am uitat in spate si scria ca rezultatul corect trebuie sa fie 0,2; Unde am gresit?

Multumesc !

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1 raspuns

  1. GreatMath
    veteran (III)

    \begin{array}{l} \left( {\frac{2}{{\sqrt {44} }} - \frac{3}{{\sqrt {99} }} + \frac{{10}}{{\sqrt {1100} }}} \right):\left( {5 \times \frac{1}{{\sqrt {11} }}} \right)\\ \frac{2}{{\sqrt {44} }} - \frac{3}{{\sqrt {99} }} + \frac{{10}}{{\sqrt {1100} }} = \frac{1}{{\sqrt {11} }}\left( {\frac{2}{{\sqrt 4 }} - \frac{3}{{\sqrt 9 }} + \frac{{10}}{{\sqrt {100} }}} \right) = \frac{1}{{\sqrt {11} }}\\ \left( {\frac{1}{{\sqrt {11} }}} \right):\left( {5 \times \frac{1}{{\sqrt {11} }}} \right) = \left( {\frac{1}{{\sqrt {11} }}} \right) \times \left( {\frac{{\sqrt {11} }}{5}} \right) = \frac{1}{5} = 0.2 \end{array}

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