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BiaBianca
Pe: 2014-01-22T06:15:45+02:00 In: In:

Exercitiu

\[ {\rm Rezolvati in multimea numerelor reale ecuatia ]

M-am gândit să scriu aşa: \[ a^{m - n} = a^m ]

Si am obtinut:

*** QuickLaTeX cannot compile formula:

	
	\[
	\begin{array}{l}
	 a^{m - n}  = a^m ]
	
	

*** Error message:
\begin{array} on input line 11 ended by \end{document}.
leading text: \end{document}
Improper \prevdepth.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing \cr inserted.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
You can't use `\end' in internal vertical mode.
leading text: \end{document}
\begin{array} on input line 11 ended by \end{document}.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Emergency stop.

Similare

4 raspunsuri

  1. tata2008
    maestru (V)

    BiaBianca wrote: \[ {\rm Rezolvati in multimea numerelor reale ecuatia ]

    M-am gândit să scriu aşa: \[ a^{m - n} = a^m ]

    Si am obtinut:

    *** QuickLaTeX cannot compile formula:

	
	\[
	\begin{array}{l}
	 a^{m - n}  = a^m ]
	
	

*** Error message:
\begin{array} on input line 11 ended by \end{document}.
leading text: \end{document}
Improper \prevdepth.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing \cr inserted.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
You can't use `\end' in internal vertical mode.
leading text: \end{document}
\begin{array} on input line 11 ended by \end{document}.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Emergency stop.

    \rm{\bl\\ daca ecuatie este de forma 2 - \underbrace{3^{x^2 - 1}}_{=1} = 1 \\ \Rightarrow 3^0 = 1 deci x^2-1=0 de unde x= \pm\sqrt1=\pm1 \in \mathbb{R}

  2. BiaBianca

    Cum am obtinut

        \[ 3^{x^2 - 1} = 1 \]

    ?

  4. tata2008
    maestru (V)

    BiaBianca wrote: Cum am obtinut

        \[ 3^{x^2 - 1} = 1 \]

    ?

    2 – ( ? )= 1 \rm{ unde ( ? ) = 3^{x^2-1}

  5. BiaBianca

    Multumesc!

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