Deci am urmatoarea problema. Se considera functia F:R-R, f(X)=2x+1. Determinati functia g:R-R, g(x)=ax+b, stiind ca graficele functiilor f si g sunt simetrice fata de : a)axa Ox, b) axa Oy, c) Punctul O(0,0). Explicati-mi, va rog, pas cu pas, algoritmul de rezolvare. Va multumesc mult!
vezi aici un exemplu :
M-am uitat, dar axele Ox si OY cu cine sunt egale? Acolo era dreapta x=1, dar în cazul meu care-i axa?
Axele de coordonate au dreptele de ecuatii :
*** QuickLaTeX cannot compile formula: \[\left\langle \begin{array}{l} Ox] *** Error message: \begin{array} on input line 8 ended by \end{document}. leading text: \end{document} Improper \prevdepth. leading text: \end{document} Missing $ inserted. leading text: \end{document} Missing } inserted. leading text: \end{document} Missing \cr inserted. leading text: \end{document} Missing $ inserted. leading text: \end{document} You can't use `\end' in internal vertical mode. leading text: \end{document} \begin{array} on input line 8 ended by \end{document}. leading text: \end{document} Missing } inserted. leading text: \end{document} Emergency stop.