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topan75
user (0)
Pe: 2013-07-19T15:39:06+03:00 In: In:

exercitiu

Sa se afle y din egalitatiile:
a) 320:{[340-(120-4xY)]:10+6}=10

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3 raspunsuri

  1. Minecraft
    maestru (V)

        \[\begin{array}{l} 320]:10 + 6} \right\} = 10\\ 32:\left[ {\left( {340 - 120 + 4y} \right)] = 1\\ 32:\left[ {\frac{{\left( {340 - 120 + 4y} \right)}}{{10}} + 6} \right] = 1\\ 32:\frac{{\left( {340 - 120 + 4y} \right) + 60}}{{10}} = 1\\ 32*\frac{{10}}{{\left( {340 - 120 + 4y} \right) + 60}} = 1\\ \frac{{320}}{{\left( {340 - 120 + 4y} \right) + 60}} = 1\\ 340 - 120 + 4y + 60 = 320\\ 4y = 320 - 340 + 120 - 60\\ 4y = 40\\ y = 10 \end{array}\]

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  2. tibi
    user (0)

    Sa se afle y din egalitatiile:
    a) 320:{[340-(120-4xY)]:10+6}=10
    se aplica mersul invers:
    [340-(120-4*Y):10+6=10*320
    [340-(120-4*Y)}:10+6=3200
    340-(120-4*Y):10=3200-6
    340-(120-4*Y):10=3194
    340-(120-4*Y)=3194*10
    340-(120-4*Y)=31940
    340-120+4*y=31940
    4*y=31940-220
    4*Y=31720
    y=31720:4
    Y=7930

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  4. Minecraft
    maestru (V)

    Tibi, se aplica „ordinea operatiilor cu paranteze” !

    • 0
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