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Please briefly explain why you feel this question should be reported.
Va rugam explicate, pe scurt, de ce credeti ca aceasta intrebare trebuie raportata.
Motivul pentru care raportezi utilizatorul.
Se dau matricele patratice:
2x 4y 3z
-v -2v t+3
1 z v
-x 2y x-z
3 -2 3
2 4 2
Sa se determine x,y,z,u,v,t, astfel ca A+B=C
sa inteleg ca ai urmatoarele matrice:
*** QuickLaTeX cannot compile formula: $${ A = \left( {\matrix{ {2x} & {4y} & {3z} \cr 1 & u & { - 4} \cr { - v} & { - 2v} & {t + 3} \cr } } \right) \cr B = \left( {\matrix{ 1 & z & v \cr { - y} & { - v} & x \cr { - x} & {2y} & {x - z} \cr } } \right) \cr C = \left( {\matrix{ 3 & { - 2} & 3 \cr 2 & 3 & { - 3} \cr 2 & 4 & 2 \cr } } \right) \cr {\rm{In general: }}A = \left( {\matrix{ {{a_{11}}} & {{a_{12}}} \cr {{a_{21}}} & {{a_{22}}} \cr } } \right),B = \left( {\matrix{ {{b_{11}}} & {{b_{12}}} \cr {{b_{21}}} & {{b_{22}}} \cr } } \right) \Leftrightarrow A + B = \left( {\matrix{ {{a_{11}} + {b_{11}}} & {{a_{12}} + {b_{12}}} \cr {{a_{21}} + {b_{21}}} & {{a_{22}} + {b_{22}}} \cr } } \right) \cr A + B = C \Leftrightarrow \left( {\matrix{ {2x} & {4y} & {3z} \cr 1 & u & { - 4} \cr { - v} & { - 2v} & {t + 3} \cr } } \right) + \left( {\matrix{ 1 & z & v \cr { - y} & { - v} & x \cr { - x} & {2y} & {x - z} \cr } } \right) = \left( {\matrix{ 3 & { - 2} & 3 \cr 2 & 3 & { - 3} \cr 2 & 4 & 2 \cr } } \right) \cr \Leftrightarrow {\rm{folosind regula de aduare:}}\left\{ \matrix{ 2x + 1 = 3{\rm{ }}[1] \hfill \cr 4y + z = - 2 \hfill \cr 3z + v = 3 \hfill \cr 1 - y = 2{\rm{ [3]}} \hfill \cr u - v = 3 \hfill \cr - 4 + x = - 3{\rm{ [2]}} \hfill \cr - v - x = 2 \hfill \cr - 2v + 2y = 4 \hfill \cr t + 3 + x - z = 2 \hfill \cr} \right.{\rm{din [1] si [2] si [3]}} \Rightarrow \left\{ \matrix{ x = 1 \hfill \cr y = - 1 \hfill \cr} \right. \Rightarrow \left\{ \matrix{ - 4 + z = - 2 \Rightarrow z = 2 \hfill \cr 3z + v = 3{\rm{ }} \hfill \cr u - v = 3{\rm{ }} \hfill \cr \left. \matrix{ - v - 1 = 2 \hfill \cr - 2v - 2 = 4 \hfill \cr} \right| \Rightarrow v = - 3 \hfill \cr t - z = - 2 \hfill \cr} \right. \cr} $$ *** Error message: Package amsmath Error: Old form `\matrix' should be \begin{matrix}. leading text: A = \left( {\matrix Misplaced alignment tab character &. leading text: {2x} & Misplaced alignment tab character &. leading text: {2x} & {4y} & Misplaced \cr. leading text: {2x} & {4y} & {3z} \cr Misplaced alignment tab character &. leading text: 1 & Misplaced alignment tab character &. leading text: 1 & u & Misplaced \cr. leading text: 1 & u & { - 4} \cr Misplaced alignment tab character &. leading text: { - v} & Misplaced alignment tab character &. leading text: { - v} & { - 2v} & Misplaced \cr. leading text: { - v} & { - 2v} & {t + 3} \cr Misplaced \cr. leading text: } } \right) \cr Package amsmath Error: Old form `\matrix' should be \begin{matrix}.De aici cred ca te descurci si singur..esti a 11a ..