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waLLer
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Pe: 2009-09-22T18:52:55+03:00 In: In:

Module

Module

| x – 3 | =
| -2x+4 | =
| 1-x |+2 =
| -x+3 |+3x =

f : R->R,f(x)=1-2x+| x |
f (0) =
f (1) =
f (-1) =

Sisteme

{-X+2y=0 ( acolada cuprinde cele 2 ecuatii )
{ X+4y=1

{2X+3y=6 ( acolada cuprinde cele 2 ecuatii )
{ x-2y=4

{ X-3>(sau egal) cu 0 ( acolada cuprinde cele 2 inecuatii )
{-2X+4<0

{ -X+6>(sau egal) cu 2X ( acolada cuprinde cele 2 inecuatii)
{ -3<X

{ X+2<(sau egal) cu -3 ( acolada cuprinde cele 2 inecuatii)

1
{ ______ x+4>(sau egal) cu 1
2

Am nevoie de rezolvare pana maine seara pt ca nu stiu tema … Va rog 🙁( ca imi da 2 . Salvati-ma please

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1 raspuns

  1. ali
    maestru (V)

    |x – 3|=

        \[ \begin{array}{l} \left| {x - 3} \right| = \left\{ \begin{array}{l} x - 3,{\rm{ pentru }}x - 3 \ge 0 \\ - (x - 3),{\rm{ pentru }}x - 3 < 0 \\ \end{array} \right. \\ = \left\{ \begin{array}{l} x - 3,{\rm{ pentru }}x \ge 3,adica{\rm{ x}} \in \left[ {3,\infty } \right) \\ - (x - 3),{\rm{ pentru }}x < 3,x \in \left( { - \infty ,3} \right) \\ \end{array} \right. \\ \end{array} \]

    Orice modul se defineste ca:

        \[ \left| {E(x)} \right| = \left\{ \begin{array}{l} E(x),{\rm{ pentru }}E(x) \ge 0 \\ - E(x),{\rm{ pentru }}E(x) < 0 \\ \end{array} \right. \]

    De fapt, waLLer, notiunea de modul se studeaza in clasa a-VII-a.

    f : R->R,f(x)=1-2x+| x |
    f (0) =


    Pur si simlu inlocuiesti x cu valoarea indicata,

        \[ f(0) = 1 - 2 \cdot 0 + |0| = 1 - 0 + 0 = 1 \]

    {-X+2y=0
    { X+4y=1 

    *** QuickLaTeX cannot compile formula:
\[
	\begin{array}{l}
	 \left\{ \begin{array}{l}
	  - x + 2y = 0{\rm{ }} \\
	 {\rm{ }}x + 4y = 1 \\
	 \end{array} \right. \\
	 adunam{\rm{ prima relatia la ultima]
	

*** Error message:
\begin{array} on input line 9 ended by \end{document}.
leading text: \end{document}
Improper \prevdepth.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing \cr inserted.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
You can't use `\end' in internal vertical mode.
leading text: \end{document}
\begin{array} on input line 9 ended by \end{document}.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Emergency stop.

    { X-3>(sau egal) cu 0 ( acolada cuprinde cele 2 inecuatii )
    {-2X+4<0 

    *** QuickLaTeX cannot compile formula:
\[
	\begin{array}{l}
	 \left\{ \begin{array}{l}
	 x - 3 \ge 0{\rm{ }} \\
	  - 2x + 4 < 0 \\
	 \end{array} \right. \\
	 R{\rm{ezolvam cele doua inecuatii separat]
	

*** Error message:
\begin{array} on input line 9 ended by \end{document}.
leading text: \end{document}
Improper \prevdepth.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Missing \cr inserted.
leading text: \end{document}
Missing $ inserted.
leading text: \end{document}
You can't use `\end' in internal vertical mode.
leading text: \end{document}
\begin{array} on input line 9 ended by \end{document}.
leading text: \end{document}
Missing } inserted.
leading text: \end{document}
Emergency stop.

    Un site unde explica detaliat notiuni primare in matematica il gasesti http://meditatiionline.ro/1-211-2414-1-0-Probleme_rezolvate_la_matematica-Sisteme_de_inecuatii_de_gradul_I_rezolvat.html#l_211 exercitii rezolvate pas cu pas cu indicatii cu tot.

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