![\[ \sqrt {x^4 - 5x^2 + 4} = 0 \]](https://anidescoala.ro/wp-content/ql-cache/quicklatex.com-3c80272e27dac82288d5c71cbb7c692a_l3.png "Rendered by QuickLaTeX.com")
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Va rugam explicate, pe scurt, de ce credeti ca aceasta intrebare trebuie raportata.
Motivul pentru care raportezi utilizatorul.
Rezolvare:
Ridicam la a doua, ecuatia devine:
Aceasta ecuatie se rezolva prin 2 metode, cea mai simpla este:
*** QuickLaTeX cannot compile formula: \[ \begin{array}{l} x^4 - 5x^2 + 4 = 0 \\ x^4 - x^2 - 4x^2 + 4 = 0 \\ x^2 (x^2 - 1) - 4(x^2 - 1) = 0 \\ \left\{ \begin{array}{l} x^2 - 1 = (x - 1)(x + 1) \\ x^2 - 4 = (x - 2)(x + 2) \\ \end{array} \right. \uparrow \\ (x^2 - 1)(x^2 - 4) = 0 \\ (x - 1)(x + 1)(x - 2)(x + 2) = 0 \\ \underline \begin{array}{l} x_1 = 1 \\ x_2 = - 1 \\ x_3 = 2 \\ x_4 = - 2 \\ \end{array} \\ \end{array} \] *** Error message: Argument of \begin has an extra }. leading text: \underline \begin Paragraph ended before \begin was complete. leading text: \underline \begin Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted. leading text: x Extra }, or forgotten $. leading text: x Missing } inserted.Multumesc pentru raspuns.
sau
Ridicam radicalul la patrat si ecuatia devine:
4 2
X – 5X + 4 = 0
2
Notam : X = t
2
t – 5 t + 4 = 0
delta = 25 – 16
= 9
t1 = (5 +3) / 2
= 4
t2 = (5-3) / 2
1
vom obtine :
2
X = 4 => X1= +2
=> X2 = -2
2
X = 1 => X3 = 1
=> X4 =-1
Da